(4/5)x^2+12=5

Solution for (4/5)x^2+12=5 equation:

(4/5)x^2+12=5

We move all terms to the left:

(4/5)x^2+12-(5)=0


Domain of the equation: 5)x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/5)x^2+12-5=0

We add all the numbers together, and all the variables

(+4/5)x^2+7=0

We multiply all the terms by the denominator


(+4+7*5)x^2=0

We add all the numbers together, and all the variables

39x^2=0

a = 39; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·39·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{78}=0$